Question

сроочно помогите пожалуйста надо найти 150%
6,62^2+5,4*3,38+1,22*3,38/20,1^2-13^2+33,1*12,9

Answer 1

$(6.62^2+ 5.4 *3.38 + 1.22 *3.38 )/(20.1^2 - 13^2+ 33.1*12.9)= \ \ frac{6.62^2+3.38(5.4+1.22)}{(20.1-13)(20.1+13)+33.1*12.9} = \ \ frac{6.62^2+3.38*6.62}{7.1*33.1+33.1*12.9} =frac{6.62(6.62+3.38)}{33.1(7.1+12.9)} =frac{6.62*10}{33.1*20} = frac{6.62}{66.2} =0.1$

0.1*150/100=0.15