Question

Помогите решить
1)3^6-x=3^3x-2
2)(1/2)^x+1=4
3)(2/5)^x=1
4)3^x=27
5)4^x=128

Answer 1

1)
${3}^{6 - x} = {3}^{3x - 2} \ 6 - x = 3x - 2 \ 4x = 8 \ x = frac{8}{4} = 2$
2)
${( frac{1}{2}) }^{x + 1}= 4 \ {(2)}^{ - x - 1} = {2}^{2} \ - x - 1 = 2 \ - x = 3 \ x = - 3$
3) х = 0

4) x = 3

5) x =
${4}^{x} = 128 \ {2}^{2x} = {2}^{7} \ 2x = 7 \ x = frac{7}{2} = 3.5$

Answer 2

вот решениеееееееееее