Question

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Answer 1

$10^{2+frac{1}{2}lg75-2lg(2sqrt[4]{3})}$

$10^{2+lgsqrt{75}-2lgsqrt[4]{48}}$

$10^{2+lgsqrt{75}-lgsqrt{48}}$

$10^{lg100+lgsqrt{frac{75}{48}}} =10^{lg100+lg1.25}$

$10^{lg125}=125$

Ответ: 125