Question

решите 3 часть задания

Answer 1

12.a)    $5sqrt{0,6} =sqrt{5^2}cdot sqrt{0,6} =sqrt{25cdot 0,6}= sqrt{15}$

12.б)    $11sqrt{dfrac{2}{11}} =sqrt{11^2}~cdot sqrt{dfrac{2}{11}} =sqrt{dfrac{11^2 cdot2}{11}} =sqrt{22}$

12.в)    $dfrac{1}{2}sqrt{6} =sqrt{Big(dfrac{1}{2}Big)^2}cdotsqrt{6} =sqrt{dfrac{6}{2^2}} =sqrt{dfrac{3}{2}}=sqrt{1,5}$

12.г)    $dfrac{2}{3}cdotsqrt{dfrac{6}{5}}=sqrt{Big(dfrac{2}{3}Big)^2}cdotsqrt{dfrac{6}{5}}=sqrt{dfrac{4}{9}cdotdfrac{6}{5}}= sqrt{dfrac{8}{15}$

Answer 2

5✓0,6=✓(5²•0,6)=
=✓(25•0,6)=✓15
11✓(2/11)=✓(2*11²/11)=✓(2*11)=✓22
½✓6=✓(6/4)=✓1,5
⅔✓(6/5)=✓(4/9)*(6/5)=✓(24/45)=✓(8/15)