Question

помогите решить 4 и 5

Answer 1

$4){8}^{5x + 1} = {7}^{5x + 1} \ ( frac{8}{7} ) {}^{5x + 1} = 1 \ ( frac{8}{7} ) {}^{5x + 1} = ( frac{8}{7} ) {}^{0} \ \ 5x + 1 = 0 \ 5x = - 1 \ \ x = - frac{1}{5} = - 0.2 \ \ 5) \ 81 {}^{x - 3} = 3 {}^{x} \ 3 {}^{4x - 4} = {3}^{x} \ 4x - 4 = x \ 4x - x = 4 \ 3x = 4 \ x = frac{4}{3} = 1 frac{1}{3}$

Answer 2

Ответ смотри в приложении.