Question

$( sqrt{3} - sqrt{5} )x > frac{4}{ sqrt{3} + sqrt{5} } \ \ \ (10 - 2 sqrt{21} )x > sqrt{7} - sqrt{3}$
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Answer 1

$(sqrt{3}-sqrt{5})x*(sqrt{3}+sqrt{5})>frac{4}{sqrt{3}+sqrt{5}}*(sqrt{3}+sqrt{5})$

(3-5)x>4

-2x>4

x<-2; x ∈ (-∞;-2);

$10-2sqrt{21}x>sqrt{7}-sqrt{3}$

$(10-2sqrt{21})x*(10+2sqrt{21})>(sqrt{7}-sqrt{3})*(10+2sqrt{3*7})$

$(100-4*21)x>10sqrt{7}+14sqrt{3}-10sqrt{3}-6sqrt{7}$

$16x>4sqrt{7}+4sqrt{3}$

$x>frac{sqrt{7}+sqrt{3}}{4}$

x ∈ ($frac{sqrt{7}+sqrt{3}}{4}$;∞)