Question

Помогите 3 пожалуйстаа♥️♥️♥️

Answer 1

1).16x^22y^10=(4x^11y^5)^2; 2). -0,064a^6b^30c^12=(-0,4a^2b^10c^4)^3.

Answer 2

$1)16x^{22}y^{10}=(4x^{11}y^{5})^{2}\\2)-0,064a^{6}b^{30}c^{12}=(-0,4a^{2}b^{10}c^{4})^{3}$