Question

ПОМОГИТЕ ДАЮ 40БАЛОВ НА СЕГОДНЯ！

Answer 1

$displaystylett 5) frac{x}{12x-3}+frac{x}{16x-4}=frac{x}{3(4x-1)}+frac{x}{4(4x-1)}=frac{4x+3x}{12(4x-1)}= \\\ {} =frac{7x}{48x-12}\\\ 6) frac{y}{4x^2-3xy}-frac{x}{4xy-3y^2}=frac{y}{x(4x-3y)}-frac{x}{y(4x-3y)}=frac{y^2-x^2}{xy(4x-3y)}=\\\{} =frac{y^2-x^2}{4x^2y-3xy^2} \\\ 7) frac{5}{x-3}+frac{1}{x+3}+frac{6}{x^2-9}=frac{5(x+3)}{x-3}+frac{1(x-3)}{x+3}+frac{6}{(x-3)(x+3)}=$

$displaystylett {} =frac{5x+15+x-3+6}{(x-3)(x+3)}=frac{6x+18}{(x-3)(x+3)}=frac{6(x+3)}{(x-3)(x+3)}=frac{6}{x-3}$

Answer 2

спасибі

Answer 3

а ви щe зможeтe мeні допомогти？