Question

Помогите пожалуйста

Answer 1

(x+2)^2 = 2(x+2) + 3

(x+2)^2 - 2(x+2) - 3 = 0

Подставляем t = (x+2)

t^2 - 2t - 3 = 0

D = 4 + 12 = 16

t = (2+4)/2 = 3

t = (2-4)/2 = -1

x+2 = 3

x+2 = -1

x = 1

x = -3