Question

1-sin2x=0
помогите пожалуйста

Answer 1

1 - sin2x = 0

- sin2x = - 1

sin2x =  1

2x = (-1)ⁿarcsin 1 + πn  n∈Z

2x = (-1)ⁿ π/2 + πn  n∈Z

x = (-1)ⁿ π/4 + π/2*n  n∈Z