Question

Решите пожалуйста три этих уравнения. С расчетом.

Answer 1

$5.) \ x {}^{2} - 3x + 2 = 0 \ d = 3 {}^{2} - 4 times 2 = 9 - 8 = 1 \ x1 = frac{3 - 1}{2} = frac{2}{2} = 1 \ x2 = frac{3 + 1}{2} = frac{4}{2} = 2 \ 6.) \ 9x {}^{2} - 6x + 1 =0 \ d = 6 {}^{2} - 4 times 9 = 36 - 36 = 0 \ x = frac{6 - 0}{18} = frac{6}{18} = frac{1}{3} \ 7. \ 3x {}^{2} - 4x + 1 = 0 \ d = 4 {}^{2} - 3 times 4 = 16 - 12 = 4 \ sqrt{4} = 2 \ x1 = frac{4 - 2}{6} = frac{2}{6} = frac{1}{3} \ x2 = frac{4 + 2}{6} = frac{6}{6} = 1$