Question

а) √x + √y при x= 9^25 (дробь) y= 0,36

б) √4–2a при а=2, –22,5

Answer 1

$1); ; sqrt{x}+sqrt{y}=sqrt{frac{9}{25}}+sqrt{0,36}=frac{3}{5}+sqrt{frac{36}{100}}=frac{3}{5}+frac{6}{10}=frac{12}{10}=1,2\\\2); ; sqrt{4-2a}=sqrt{4-2cdot 2}=sqrt{4-4}=sqrt0=0\\sqrt{4-2a}=sqrt{4-2cdot (-22,5)}=sqrt{4+45}=sqrt{49}=7$