Question

x⁴-3x⁴+2x²

x²y+3xy×x+x²

Answer 1

${x}^{4} - 3 {x}^{4} + 2 {x}^{2} = - 2 {x}^{4} + 2 {x}^{2} = \ - 2 {x}^{2} ( - 2 {x}^{2} - 1)$
${x}^{2} y + 3 {x}^{2} y + {x}^{2} = 4 {x}^{2} y + {x}^{2} = \ {x}^{2}(4y + 1)$