Question

Sin3x=√2/2
Помогите!!!

Answer 1

$sin 3x=dfrac{sqrt{2}}{2}\ \ 3x=(-1)^kcdot arcsindfrac{sqrt{2}}{2}+pi k,k in mathbb{Z}\ \ 3x=(-1)^kcdotdfrac{pi}{4}+pi k,k in mathbb{Z}\ \ x=(-1)^kcdotdfrac{pi}{12}+dfrac{pi k}{3},k in mathbb{Z}$