Question

Помогите с последним примером, в файле

Answer 1

$frac{1}{x-5} +frac{1}{x+3} =0\\frac{1(x+3)+1(x-5)}{(x-5)(x+3)} =0\\frac{x+3+x-5}{(x-5)(x+3)} =0\\frac{2x-2}{(x-5)(x+3)} =0\\1)ODZ:\\x-5neq 0\xneq 5\\x+3neq 0\xneq -3\\2)2x-2=0\2x=2|:2\x=1\\Otvet:1$

Answer 2

(х+3+х–5)/(х–5)(х+3) = 0
(2х–2)/(х–5)(х+3)=0
2х–2=0; (х–5)(х+3)#0
х=1. х#5; х#–3