Question

ПОМОГИТЕ СРОЧНО!!!
$3y^{2} + 4y = 0$
$3 - 12x^{2} = 16x$
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Answer 1

$3y^{2}+4y=0\ y(3y+4)=0\\left { {{y=0} atop {3y=-4}} right. \left { {{y=0} atop {y=-frac{4}{3} }} right.$

$3-12x^{2} =16x\12x^{2} +16x-3=0\D/4=k^{2}-ac=64+36=100\left { {{x=frac{1}{6} } atop {x=-frac{3}{2} }} right.$

Answer 2

СПАСИБО БОЛЬШОЕ!!!