Question

(12-y)*y=32
Решите плиз

Answer 1

(12-у) × у = 32

12у - у^2 = 32

-у^2 + 12 - 32 = 0 | × (-1)

у^2 - 12 + 32 = 0

D = b^2 - 4ac =12^2 - 4 × 1 × 32 = 144 - 128 = 16

$y1 = frac{ - b - sqrt{d} }{2a}$

y1 = (12 - 4) / 2 = 4

$y2 = frac{ - b + sqrt{d} }{2a}$

y2 = (12 + 4) / 2 = 8

Ответ: у = 4; у = 8.