Question

4х²-8х+4=0 х²+6х-7=0 3х²+6х+3=0 х²+8х+16=0 18х²-9х=0

Answer 1

$4 {x}^{2} - 8x + 4 = 0 div 4 \ {x}^{2} - 2x + 1 = 0 \ d = 4 - 4 = 0$

$x = frac{2 + 0}{2} = frac{2}{2} = 1$

${x}^{2} + 6x - 7 = 0 \ d = 36 + 28 = 64 = 4 \ x1 = frac{ - 6 + 4}{2} = - frac{2}{2} = - 1$

$x2 = frac{ - 6 - 4}{2} = - frac{10}{2} = - 5$

$3 {x}^{2} + 6x + 3 = 0 div 3 \ {x}^{2} + 2x + 1 = 0 \ d = 4 - 4 = 0 \ x = frac{2 + 0}{2} = frac{2}{2} = 1$

х=1

${x}^{2} + 8x + 16 = 0 \ d = 64 - 64 = 0 \ x = frac{8 + 0}{2} = frac{8}{2} = 4$

${18x}^{2} - 9x = 0 \ 9x(2x - 1) = 0 \ 9x = 0 \ x = 0$

$2x - 1 = 0 \ 2x = 1 \ x = frac{1}{2} = 0.5$

Answer 2

спасибо большое

Answer 3

не за что это же легко

Answer 4

просто сомому лень решать