Question

((Решите уравнения.))

Answer 1

$a)3 {x}^{2} - 5x + 2 = 0 \ a = 3 \ b = - 5 \ c = 2$

$d = {b}^{2} - 4ac = ({ - 5})^{2} - 4 times 3 times 2 = \ = 25 - 24 = 1$

$x1 = frac{ - 5 + 1}{6} = - frac{4}{6} = - frac{2}{3}$

$x2 = frac{ - 5 - 1}{6} = - frac{6}{6} = - 1$

Б)

${x}^{2} + 3x + 3 = 0 \ d = 9 - 12 = - 3$

Нет решения

В)

$5 {y}^{2} - 4y = 1 \ y(5y - 4) = 1 \ y = 1$

$5y - 4 = 1 \ 5y = 1 + 4 \ 5y = 5 \ y = 5 div 5 \ y = 1$