Question

3(x-2)-2(y+1)=-1 5(x+3)-8(y-2)=45 пж​

Answer 1

3(x-2)-2(y+1)=-1

3х-6-2у-2=1

3х-2у=9

5(x+3)-8(y-2)=45

5х+15-8у+16=45

5х-8у=14

{3х-2у=9 |*2

{5х-8у=14

{6х-4у=18| из первого отнять второе

{5х-8у=14

х+4у=4

х=4-4у

3(4-4у)-2у=9

12-12у-2у=9

-14у=-3

у=3/14

х=4-4*3/14=56/14-12/14=44/14=22/7=3 1/7

ответ:(3 1/7;3/14)