Question

f(x)=32*x^-5, x0=2 обчисліть похідну

Answer 1

F(x) = 32*x⁻⁵;   x₀ = 2;

F'(x) = 32 * (-5) * x⁻⁶ = -160/x⁶;

F'(2) = -160/2⁶ = -160/64 = -2,5.