Question

Помогите пожалуйста ​

Answer 1

$(sqrt{27}-sqrt{8}+sqrt{32}-sqrt{12})^{-2}=\(3sqrt{3}-2sqrt{2}+4sqrt{2}-2sqrt{3})^{-2}=\(sqrt{3}+2sqrt{2})^{-2}=frac{1}{3+8+4sqrt{6}}^{(11-4sqrt{6}}=\frac{11-4sqrt{6}}{121-96}=frac{11-4sqrt{6}}{25}\Otvet:frac{11-4sqrt{6}}{25}.$

$frac{11-4sqrt{6}}{25}=frac{4(11-4sqrt{6})}{100};sqrt{6}approx2.45\frac{11-4sqrt{6}}{25}approx frac{4(11-9.8)}{100}=frac{4*1.2}{100}=0.048$