Question

Решите пожалуйста В1 с обеих вариантов

Answer 1

B1

$1)\frac{1}{(b-y)(y-5)}-\frac{1}{(b-y)(b-5)}-\frac{1}{(b-5)(y-5)}=\frac{b-5-(y-5)-(b-y)}{(b-y)(y-5)(b-5)}=\frac{b-5-y+5-b+y}{(b-y)(y-5)(b-5)}=0\\\\2)0*\frac{b^{2}-9y^{2}}{b^{4}+y^{4}}=0$

B1

$1)\frac{1}{(a-x)(x-1)}-\frac{1}{(a-x)(a-1)}-\frac{1}{(a-1)(x-1)}=\frac{a-1-(x-1)-(a-x)}{(a-x)(x-1)(a-1)}=\frac{a-1-x+1-a+x}{(a-x)(x-1)(a-1)}=\frac{0}{(a-x)(x-1)(a-1)}=0\\\\2)0*\frac{a^{3}-8x^{3}}{a^{4}+b^{4}}=0$