Question

√0,16+√(-9)²+√2$\frac{1}{4}$

Answer 1

$\sqrt{0,16}+\sqrt{(-9)^2}+\sqrt{2\frac{1}{4}}=\sqrt{(0,4)^2}+|-9|+\sqrt{\frac{9}{4}}=0,4+9+\frac{3}{2}=\\\\=\frac{2}{5}+9+\frac{3}{2}=\frac{4+90+15}{10}=\frac{109}{10}=10,9\\\\\\P.S.\; \; \sqrt{a^2}=|a|\; \; \Rightarrow \; \; \; \sqrt{(-9)^2}=|-9|=9\\\\ili:\; \; \; \sqrt{(-9)^2}=\sqrt{+81}=9$