Question

разложите на множители


a+b+p(a+b)

x+2a(x-y)-y

a(a+b)-5a-5b

8x-8y+ax-ay

pq-x-px+q

Answer 1

$1)\; \; (a+b)+p(a+b)=(a+b)(1+p)\\\\2)\; \; x+2a(x-y)-y=(x-y)+2a(x-y)=(x-y)(1+2a)\\\\3)\; \; a(a+b)-5a-5b=a(a+b)-5(a+b)=(a+b)(a-5)\\\\4)\; \; 8x-8y+ax-ay=8(x-y)+a(x-y)=(x-y)(8+a)\\\\5)\; \; pq-x-px+q=(pq-px)+(q-x)=p(q-x)+(q-x)=\\\\=(q-x)(p+1)$

Answer 2

Ответ:

a+b+p·(a+b) =(a+b)·(1+p)

x+2·a·(x-y)-y =(x-y)·(1+2·a)

a·(a+b)-5·a-5·b=(a+b)·(a-5)

8·x-8·y+a·x-a·y=(x-y)·(8+a)

p·q-x-p·x+q= (p+1)·(q-x)

Объяснение:

a+b+p·(a+b) =1·(a+b)+p·(a+b)=(a+b)·(1+p)

x+2·a·(x-y)-y =1·(x-y)+2·a·(x-y)=(x-y)·(1+2·a)

a·(a+b)-5·a-5·b =a·(a+b)-5·(a+b)=(a+b)·(a-5)

8·x-8·y+a·x-a·y =8·(x-y)+a·(x-y)=(x-y)·(8+a)

p·q-x-p·x+q= p·q+q -x-p·x=q·(p+1)-x(1+p)=(p+1)·(q-x)