Question

пожалуйста сделайте тест

Answer 1

1 . A)

2 . Б) 2а-10=0

2а=10

а=10÷2

а= 5

3 . В)

$0 = \frac{x + 2}{x {}^{2} - 1} \\ 0 = \frac{x + 2}{x {}^{2} - 1} \\ x = - 1 \\ x = 1 \\ \frac{x + 2}{x {}^{2} - 1} = 0 \\ x + 2 = 0 \\ x = - 2$

4 . Б)

$\frac{21a {}^{6} }{14a {}^{3} } = \frac{3a {}^{2} }{2}$

5 . Г)

$\frac{5b - 15}{b {}^{2} - 9} \\ \frac{5(b - 3)}{(b - 3)(b + 3)} \\ \frac{5}{b + 3}$

6 . А)

$\frac{12c {}^{2} - 4c}{3c - 1} \\ \frac{4c(3c - 1)}{3c - 1} \\ 4c$

7 . В)

$\frac{5x}{x - 2} - \frac{10}{x - 2} \\ \frac{5x - 10}{x - 2} \\ \frac{5(x - 2)}{x - 2} \\ 5$

8.

$\frac{4 - m}{m - 3} + \frac{2m - 5}{3 - m } \\ \frac{4 - m - 2m + 5}{m - 3} \\ \frac{9 - 3m}{m - 3} \\ \frac{ - 3m + 9}{m - 3} \\ \frac{ - 3(m - 3)}{m - 3} \\ - 3$

9 .

$\frac{3n {}^{2} }{n - 6} - 3n \\ \frac{3n {}^{2} - 3n(n - 6)}{n - 6} \\ \frac{3n {}^{2} - 3n {}^{2} + 18n }{n - 6 } \\ \frac{18n}{n - 6}$

10.

$\frac{2m + 1}{3m - 2} - \frac{3m {}^{2} - 2m - 2 }{(3m - 2) {}^{2} } \\ \frac{2m + 1}{3m - 2} - \frac{3m(m + 1) - 2(m + 1)}{(3m - 2) {}^{2} } \\ \frac{2m + 1}{3m - 2} - \frac{(m + 1)(3m - 2)}{(3m - 2) {}^{2} } \\ \frac{2m + 1}{3m - 2} - \frac{m + 1}{3m - 2} \\ \frac{2m + 1}{3m - 2} - \frac{m + 1}{3m - 2} \\ \frac{2m + 1 - (m + 1)}{3m - 2} \\ \frac{2m + 1 - m - 1}{3m - 2} \\ \frac{m}{3m - 2}$

11.

$\frac{a - 12}{a {}^{2} + 4a } - \frac{a - 4}{a} + \frac{a}{a + 4} \\ \frac{a - 12}{a(a + 4)} - \frac{a - 4}{a} + \frac{a}{a + 4} \\ \frac{a - 12 - (a + 4)(a - 4) + a {}^{2} }{a(a + 4)} \\ \frac{a - 12 - (a {}^{2} - 16) + a {}^{2} }{a (a + 4)} \\ \frac{a - 12 - a {}^{2} + 16 + a {}^{2} }{a(a + 4)} \\ \frac{a - 12 - a {}^{2} + 16 + a {}^{2} }{a(a + 4)} \\ \frac{a + 4}{a(a + 4)} \\ \frac{1}{a}$