Question

РЕБЯТА СРОЧНО !!! ПРОШУ​

Answer 1

$\frac{4}{a-3} +\frac{2a}{3+a}=\frac{4(a+3)+2a(a-3)}{(a-3)(a+3)} =\frac{4a+12 + 2a^{2}-6a}{a^{2}-3^{2} }=\frac{2a^{2}-2a+12}{a^{2}-3^{2} }$