Question

51 2/5-22,68÷0,45+(3/8+7/20)×1 1/29=

Answer 1

$51\frac{2}{5}-22,68:0,45+(\frac{3}{8}+\frac{7}{20})*1\frac{1}{29} =\\\\51\frac{2}{5}-22\frac{17}{25}:\frac{9}{20}+(\frac{15+14}{40})*\frac{30}{29}=\\\\51\frac{2}{5}-\frac{567}{25}*\frac{20}{9}+\frac{29}{40}*\frac{30}{29}=\\\\51\frac{2}{5}-\frac{63*4}{5}+\frac{3}{4}=\\\\51\frac{2}{5}-50\frac{2}{5}+\frac{3}{4}=\\\\1\frac{3}{4}$

Ответ: 1,75

Answer 2

Примеры цепочкой на десятичные дроби.