Question

Срочно! Прошу помочь

Answer 1

Ответ:

$\frac{9}{17x} + \frac{9}{17x^{4}}$

Объяснение:

$a1 = \frac{9}{17x}$

$a2 = \frac{a1}{x} = \frac{9}{17x} : x = \frac{9}{17x} : \frac{x}{1} = \frac{9}{17x} * \frac{1}{x} = \frac{9*1}{17x*x}  = \frac{9}{17x^{2}}$

$a3 = \frac{a2}{x} = \frac{9}{17x^{2} } : x = \frac{9}{17x^{2} } : \frac{x}{1} = \frac{9}{17x^{2} } * \frac{1}{x} = \frac{9*1}{17x^{2} *x}  = \frac{9}{17x^{3}}$

$a4 = \frac{a3}{x} = \frac{9}{17x^{3} } : x = \frac{9}{17x^{3} } : \frac{x}{1} = \frac{9}{17x^{3} } * \frac{1}{x} = \frac{9*1}{17x^{3} *x}  = \frac{9}{17x^{4}}$

$y = a1 + a4 = \frac{9}{17x} + \frac{9}{17x^{4}}$