Question

Решите девятый номер

Answer 1

Ответ:

$-\frac{2}{3}-\frac{\sqrt{5}}{3}i; -\frac{2}{3}+\frac{\sqrt{5}}{3}i$

Объяснение:

$3x^2 + 4x + 3 = 0;\\D = 16-36 = -20;\\x_1 = \frac{-4-\sqrt{-20}}{6} = -\frac{2}{3}-\frac{\sqrt{5}}{3}i;\\x_2 = \frac{-4+\sqrt{-20}}{6} = -\frac{2}{3}+\frac{\sqrt{5}}{3}i;$