Question

помогите с тригонметрией! ​

Answer 1

$cos(2x-\frac{\pi }{6} )=\frac{\sqrt{2} }{2} \\2x-\frac{\pi }{6} =\pm\frac{\pi }{4}+2\pi{k}, k\in{Z}\\2x=\pm\frac{\pi }{4} +\frac{\pi }{6} +2\pi {k}, k\in{Z}\\x=\pm\frac{\pi }{8} +\frac{\pi }{12}+\pi{k}, k\in{Z}\\x=\frac{5\pi }{24}+\pi{k}, x=-\frac{\pi }{24}+\pi{k}, k\in{Z}$