Question

Срочно помогите 21 номер!

Answer 1

$\frac{\sqrt{4x-x^2} }{x-1}\; \; \to \; \; \; \left \{ {{4x-x^2\geq 0} \atop {x-1\ne 0}} \right.\; \; \left \{ {{x(x-4)\leq 0} \atop {x\ne 1}} \right.\; \; \left \{ {{x\in [\, 0\, ,\, 4\, ]} \atop {x\ne 1}} \right.\; \; \Rightarrow \\\\x\in [\, 0\,,\, 1)\cup (1,\, 4\, ]\\\\\\x(x-4)\leq 0\; \; ,\; \; x_1=0\; ,\; x_2=4\\\\znaki\; x(x-4):\; \; \; +++[\, 0\, ]---[\, 4\, ]+++\\\\x\in [\, 0,4\, ]\\\\Otvet:\; \; x\in [\, 0,1\, )\cup (1,4\, ]\; .$