Question

Решите уравнение 2x(x+4)-16x=12-4x² и 2x(3x+4)-16x=12-4x²

Answer 1

$\bullet 2x(x+4)-16x=12-4x^2\Leftrightarrow 2x^2+8x-16x=12-4x^2\Leftrightarrow \\\Leftrightarrow 6x^2-8x-12=0\Leftrightarrow 3x^2-4x-6=0\\D_1=4+18=22\\x=\frac{2\pm \sqrt{22}}{3}\\\bullet 2x(3x+4)-16x=12-4x^2\Leftrightarrow 6x^2+8x-16x=12-4x^2\Leftrightarrow \\\Leftrightarrow 5x^2-4x-6=0\\D_1=4+30=34\\x=\frac{2\pm \sqrt{34}}{5}$