Question

решите примеры с очень детальным разъяснениям !!!!!срочно!!!​

Answer 1

$1)frac{x}{y} = t \ t + frac{1}{t} = frac{26}{5} \ frac{ {t}^{2} + 1 }{t} = frac{26}{5} \ 5 {t}^{2} +5 = 26 t \ 5 {t}^{2} - 26t + 5 = 0 \ dis = 676 - 100 = 576 \ t1 = frac{26 + 24}{10} = 5 \ t2 = frac{26 - 24}{10} = frac{1}{5} \ a)frac{x}{y} = 5 : : : : x = 5y \ ( {5y})^{2} - {y}^{2} = 96 \ 24 {y}^{2} = 96 \ {y}^{2} = 4 \ y1 = 2 : : : : : : : : : : : : : x1 = 5 times 2 = 10\ y2 = - 2 : : : : : : : : : : x2 = 5 times - 2 = - 10 \ b) frac{x}{y} = frac{1}{5} \ y = 5x \ {x}^{2} = 25 {x}^{2} = 96 \ = 24 {x}^{2} = 96 \ {x}^{2} = - 4 : net : korney \ znacit : t = frac{1}{5} : ne : udovletvoraet : usloviyu$

$frac{x}{y} = t \ t - frac{2}{t} = frac{7}{3} \ frac{ {t}^{2} - 2}{t} = frac{7}{ 3} \ 3 {t}^{2} - 6 = 7t \ 3 {t}^{2} - 7t - 6 = 0 \ dis = 121 \ t1 = frac{7 + 11}{6} = 3 \ t2 = frac{7 - 11}{6} = - frac{2}{3} \ a) frac{x}{y} = 3 \ x = 3y \ {(3y)}^{2} + {y}^{2} = 40 \ 10 {y}^{2} = 40 \ {y}^{2} = 4 \ y1 = 2 : : : : : : : x1 = 3 times 2 = 6 \ y2 = - 2 : : : : : : x2 = 3 times ( - 2) = - 6 \ b) frac{x}{y} = - frac{2}{3} \ x = - frac{2}{3} y \ {{( - frac{2}{3}y }) }^{2} + y^{2} = 40 \ frac{4}{9} {y}^{2} + {y}^{2} = 40 \ frac{13}{9} {y}^{2} = 40 \ {y}^{2} = frac{360}{13} \ y1 = frac{6 sqrt{10} }{ sqrt{13} } = frac{6 sqrt{130} }{13} \ x1 = - frac{2}{3} times frac{6 sqrt{130} }{13} = - frac{4 sqrt{130} }{13} \ y2 = - frac{ 6 sqrt{130} }{13} : : : : : : \ x2 = frac{4 sqrt{130} }{13}$

Answer 2

очень рада была помочь

Answer 3

надеюсь все там ясно тебе