Question

Помогите с математикой

Answer 1

$a * b = |a| * |b| * cos(a) = a_1b_1+a_2b_2+a_3b_3 => cos(a) = frac{a_1b_1+a_2b_2+a_3b_3}{ |a| * |b|}\|a| = sqrt{a_1^2 + a_2^2+a_3^2} = sqrt{4 + 9 +9} = sqrt{22}\|b| = sqrt{b_1^2+b_2^2+b_3^2} = sqrt{36+16+64} = sqrt{116} = 2sqrt{29}\cos(a) = frac{-12 - 12 - 24}{2sqrt{29}*sqrt{22}} = -frac{24}{sqrt{638}} neq 0 => a = arccos(-frac{24}{sqrt{638}}) neq frac{pi }{2}$

Ответ: нет