Question

Решите с решением пожалуйста​

Answer 1

324.

а)

$frac{51}{14}x=102\\ x=102:frac{51}{14}\\x=frac{102*14}{51}=2*14=28$

b)

$11x+3frac{4}{7}=2\\11x+frac{25}{7}=2\\11x=2-frac{25}{7}\\11x=frac{14}{7} -frac{25}{7}\\11x=-frac{11}{7} \\x=-frac{11}{7} :11=-frac{11}{7*11}=-frac{1}{7}$

c)

$frac{3}{8}x+frac{6}{7}=5-frac{5}{6}x\\frac{3}{8}x+frac{5}{6}x=5-frac{6}{7}\\frac{9}{24}x +frac{20}{24}x=frac{35}{7}-frac{6}{7}\\frac{29}{24}x=frac{29}{7}\\ x=frac{29}{7}:frac{29}{24}=frac{29*24}{7*29}=frac{24}{7}=3frac{3}{7}$

d)

$21(x-5)=2(10-7x)\\21x-105=20-14x\\21x+14x=20+105\\35x=125\\x=frac{125}{35}=frac{25}{7}=3frac{4}{7}$

e)

$frac{2}{1} (2x+frac{1}{3} )=2frac{1}{6}-(frac{x}{2}-frac{5}{33})\\frac{4x}{1}+frac{2}{3}=frac{13}{6} -frac{x}{2}+frac{5}{33}\\frac{4x}{1} +frac{x}{2}=frac{13}{6}+frac{5}{33}-frac{2}{3}\\frac{8x}{2}+frac{x}{2}=frac{143}{66}+frac{10}{66}-frac{44}{66}\\frac{9x}{2}=frac{109}{66}\\x=frac{109}{66}:frac{9}{2}= frac{109*2}{66*9}=frac{109}{297}$

325.

a)

$frac{15}{34}x=210\\x=210:frac{15}{34}=frac{210*34}{15}=14*34=476$

b)

$frac{7}{9}x-frac{4}{27}=frac{1}{18}\\frac{7}{9}x=frac{1}{18}+frac{4}{27} \\frac{7}{9}x=frac{3}{54}+frac{8}{54}\\frac{7}{9}x=frac{11}{54}\\ x=frac{11}{54}:frac{7}{9}=frac{11*9}{54*7}=frac{11}{6*7}=frac{11}{42}$

c)

$frac{3}{4}x+frac{4}{7}=x-1frac{3}{14}\\frac{3}{4}x-x=-1frac{3}{14}-frac{4}{7}\\frac{3x}{4}-frac{4x}{4}=-frac{17}{14}-frac{8}{14}\\-frac{x}{4}=-frac{25}{14} \\ x= frac{25}{14}:frac{1}{4}=frac{25*4}{14}=frac{25*2}{7}=frac{50}{7}=7frac{1}{7}$

d)

$12-3(2x+7)=2-9x\\12-6x-21=2-9x\\9x-6x=2+21-12\3x=11\x=frac{11}{3}=3frac{2}{3}$

e)

$frac{1}{3}x-frac{13}{15}=1frac{1}{2} (x+frac{2}{3})\\frac{1}{3}x-frac{13}{15}=frac{3}{2}(x+frac{2}{3})\\frac{1}{3}x-frac{13}{15}=frac{3}{2}x+1\\frac{3}{2}x-frac{1}{3}x= -1-frac{13}{15}\\frac{9x}{6}-frac{2x}{6} =-frac{15}{15}-frac{13}{15}\\frac{7x}{6}=-frac{28}{15}\\x=-frac{28}{15}:frac{7}{6}=- frac{28*6}{15*7}=-frac{4*6}{15}=-frac{24}{15}=-frac{8}{5}$