Question

sin(2x+3п)sin(3x+3п/2)=0

Answer 1

Ответ:

$left { {{ x=frac{pi k}{2}} atop {x = frac{pi}{6} +frac{pi k}{3}}} right. , , , , k in Z$

Объяснение:

$sin(2x+3pi)=-sin2x\sin(3x+frac{3pi}{2})=-cos3x \\sin(2x+3pi)sin(3x+frac{3pi}{2})=0\\sin2xcos3x=0$

1:

$sin2x=0\x=frac{pi k}{2} , , , , k in Z$

2:

$cos3x=0\3x=frac{pi}{2} +pi k, , , , k in Z\\x = frac{pi}{6} +frac{pi k}{3}, , , , k in Z$