Question

Приведите уравнение к виду $ax^{2}$+bx+c=0
1) (7х-1)(2+х) = (х-4)(х+4)
2) х(8-3х)= (5х-1)$^{2}$

Answer 1

1) (7х-1)(2+х)=(х-4)(х+4)
14х+7х$1)(7x-1)(2+x)=(x+4)(x-4)\ 14x+7 x^{2} -2-x= x^{2} -16\ 7 x^{2} - x^{2} +14x-x-2+16=0\ 6 x^{2} +13x+14=0\ 2)x(8-3x)=(5x-1) ^{2} \ 8x-3 x^{2} =25 x^{2} -10x+1\ -3 x^{2} -25 x^{2} +8x+10x-1=0\ -28 x^{2} +18x-1=0$