Question

действие с дробями. Помогите, даю 25 баллов. ​

Answer 1

Ответ:

1.а)5/8

б)1/3

в)3/8

г)23/30

2.а)21/2

б)5

в)1/4

г)2

Answer 2

№ 1

а)

$\frac{1}{2} +\frac{3}{4} -\frac{5}{8} = \frac{4}{8} +\frac{6}{8} -\frac{5}{8} = \frac{4}{8}+\frac{1}{8} =\frac{5}{8}$

б)

$\frac{2}{3} + \frac{1}{6} - \frac{1}{2} = \frac{4}{6} +\frac{1}{6}-\frac{3}{6} =\frac{5}{6} -\frac{3}{6} =\frac{2}{6} =\frac{1}{3}$

в)

$\frac{5}{8} -(\frac{2}{3}-\frac{5}{12} )=\frac{15}{24}-(\frac{16}{24} -\frac{10}{24} )=\frac{15}{24} -\frac{6}{24} =\frac{9}{24} = \frac{3}{8}$

г)

$\frac{1}{2} +(\frac{3}{5} -\frac{5}{12} )= \frac{30}{60} +(\frac{36}{60} -\frac{25}{60})=\frac{30}{60} +\frac{9}{60} =\frac{39}{60}=\frac{13}{20}$

№2

а)

$(\frac{1}{10} +\frac{3}{5} )*15=(\frac{1}{10} +\frac{6}{10})*15=\frac{7}{10} *15=\frac{105}{10} = 10 \frac{5}{10} = 10\frac{1}{2}$

б)

$12-(\frac{2}{3} -\frac{1}{4} )=11\frac{12}{12} -(\frac{8}{12} +\frac{3}{12} )=11\frac{12}{12} -\frac{11}{12}=11\frac{1}{12}$

в)

$\frac{1}{10} +\frac{3}{5} *\frac{1}{4} = \frac{1}{10} +\frac{3}{20}= \frac{2}{20} +\frac{3}{20} = \frac{5}{20} = \frac{1}{4}$

г)

$2\frac{1}{2} -\frac{3}{5} *\frac{5}{6} = 2\frac{3}{6} -\frac{3}{6} =2$