Question

РЕШИТК УРАВНЕНИЕ !!!!!
СРОЧНО !!!!!!

Answer 1

1)

$x^4+2x^2-3=0\\x^2=t\\t^2+2t-3=0\\t=-3\\t=1\\\\x^2=-3\\x\notin R\\\\x^2=1\\x_1=-1\\x_2=1$

2)

$\frac{x^2+14x+24}{x+12}=0, ~~x\neq -12\\\frac{x^2+12x+2x+24}{x+12}=0\\\frac{x(x+12)+2(x+12)}{x+12}=0\\\frac{(x+12)(x+2)}{x+12}\\x+2=0\\x=-2$