Question

Найдите отношение х/у $- 6,04 = ln(\frac{x*4+y*400}{x*100})$

Answer 1

$-6.04=ln\dfrac{4x+400y}{100x}\\ -6.04=ln(\dfrac{1}{25}+4*\dfrac{y}{x})\\ e^{-6.04}=\dfrac{1}{25}+4*\dfrac{y}{x}\\ e^{-6.04}-\dfrac{1}{25}=4*\dfrac{y}{x}=>\\ =>\dfrac{x}{y}=\dfrac{4}{e^{-6.04}-\dfrac{1}{25}}=\dfrac{100}{25e^{-6.04}-1}$