Question

√2x² - (2+√10)x+2√5=0

Answer 1

Ответ:

$\sqrt{2} {x}^{2} - (2 + \sqrt{10} )x + 2 \sqrt{5} = 0$

Дискриминант

$d = 4 + 4 \sqrt{10} + 10 - 8 \sqrt{10} = 14 - 4 \sqrt{10} = 1.35$

$x1 = \frac{2 + \sqrt{10} - \sqrt{1.35} }{2 \sqrt{2} } = 1.41$

$x2 = \frac{2 + \sqrt{10} + \sqrt{1.35} }{2 \sqrt{2} } = 2.24$