Question

Оооочееень нужно помогите, алгебра​

Answer 1

$\left \{ {{4(x+y)-3y=2} \atop {9(x-2y)-6x=-11}} \right. \\\\\left \{ {{4x+4y-3y=2} \atop {9x-18y-6x=-11}} \right. \\\\\left \{ {{4x+y=2}|*18 \atop {3x-18y=-11}} \right.\\\\+\left \{ {{72x+18y=36} \atop {3x-18y=-11}} \right.\\--------\\75x=25\\\\x=\frac{1}{3}\\\\y=2-4x=2-4*\frac{1}{3} =2-1\frac{1}{3}=\frac{2}{3}\\\\Otvet:\boxed{(\frac{1}{3};\frac{2}{3})}$

Answer 2

Ответ:

x=1/3; y=2/3

Объяснение:

$\left \{ {{4(x+y)-3y=2} \atop {9(x-2y)-6x=-11}} \right.\\\\\left \{ {{4x+4y-3y=2} \atop {3x-18y-6x=-11}} \right. \\\left \{ {{y=2-4x} \atop {3x-18(2-4x)=-11}} \right. \\3x-36+72x=-11\\75x=15\\x=15/75=1/3\\y=2-1/3=2/3$