Question

3√20 - 3 √12 - 2 √45 + 2 √27 √3 =
Решите 

Answer 1

$3 sqrt{4*5} -3 sqrt{4*3} -2 sqrt{9*5} +2 sqrt{27*3} =6 sqrt{5} -6sqrt{3}-6sqrt{5} +2 sqrt{81} =-6sqrt{3}+18$

Answer 2

3√20 - 3 √12 - 2 √45 + 2 √27 √3 =180-108-180+120=12