Question

4. Сократите дроби:​

Answer 1

а)

$\frac{3-b^{2}}{\sqrt{3} +b} =\frac{(\sqrt{3} -b)(\sqrt{3} +b)}{\sqrt{3} +b} =\sqrt{3} -b$

б)

$\frac{5-\sqrt{5} }{\sqrt{2}-\sqrt{10}} =\frac{(5-\sqrt{5} )(\sqrt{2} +\sqrt{10} )}{2-10} =\frac{5\sqrt{2}+5\sqrt{10} -\sqrt{10} -5\sqrt{2} }{-8} =-\frac{4\sqrt{10} }{8} =-\frac{\sqrt{10} }{2}$