Question

Алгебра номер 118 8 класс

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Answer 1

Ответ:

${2}^{ \frac{4}{5} } \times {2}^{ \frac{11}{5} } = {2}^{ \frac{4 }{5} + \frac{11}{5} } = {2}^{ \frac{4 + 11}{5} } = {2}^{ \frac{15}{5} } = {2}^{3} = 8$

$( { 7}^{ - 3} ) ^{ - \frac{2}{3} } = ( \frac{1}{7} ^{3} ) ^{ - \frac{2}{3} } = ( {7}^{3} ) ^{ \frac{2}{3} } = {7}^{3 \times \frac{2}{3} } = {7}^{2} = 49$