Question

arcsin(-√2/2)-arctan(-√3/2) вычислите, срочно

Answer 1

$arcSin(-\frac{\sqrt{2}}{2})-arctg(-\frac{\sqrt{3}}{3} )=-\frac{\pi }{4}-(-\frac{\pi }{6})=-\frac{\pi }{4}+\frac{\pi }{6}=\frac{-3\pi+2\pi}{12} =-\frac{\pi }{12}\\\\Otvet:\boxed{-\frac{\pi }{12}}$