Question

Задача 2. СРОЧНО ПОЖАЛУЙСТА!!!​

Answer 1

Ответ:

1) 13

2) 9

3) 2,5

4) $\sqrt{61}$

5) 1

Объяснение:

1) $c=\sqrt{a^{2} + b^{2}}$=$\sqrt{5^{2} + 12^{2} } = \sqrt{25+144} =\sqrt{169}=13$;

2) $c=\sqrt{a^{2} + b^{2}}$=$\sqrt{(4\sqrt{2}) ^{2} + 7^{2} } = \sqrt{4^{2} *(\sqrt{2}) ^{2} +49} =\sqrt{16*2+49}=\sqrt{81}=9$;

3) $c=\sqrt{a^{2} + b^{2}}$=$\sqrt{(0,7)^{2} + (2,4)^{2} } = \sqrt{0,49+5,76} =\sqrt{6,25}=2,5$;

4) $c=\sqrt{a^{2} + b^{2}}$=$\sqrt{5^{2} + 6^{2} } = \sqrt{25+36} =\sqrt{61}$;

5) $c=\sqrt{(\frac{5}{13})^{2} + (\frac{12}{13})^{2}} =\sqrt{\frac{25}{169} + \frac{144}{169}} = \sqrt{\frac{169}{169} }=\sqrt{1} =1$