Question

помогите пожалуйста !!!​

Answer 1

Ответ:

1. у'=х-6

2. у'= 2cosx-3x²

$3. f'(x)=1+ \frac{1}{ { \cos}^{2} x} \\ f'(\pi)=1+ \frac{1}{ \cos^{2}\pi } = \\ = 1 + \frac{1}{ { (- 1)}^{2} } = 2$

$4. \: y' = - 4 \sin \: x \\ y'( x_{0} ) = y'( \frac{\pi}{2} ) = - 4 \sin( \frac{\pi}{2} ) = - 4$

$5. \: f'(x) = \frac{2 }{( {1 - x)}^{2} } \\ f'( - 1) = \frac{2}{( {1 - ( - 1))}^{2} } = \frac{2}{4} = 0.5$

$6. \: y' = \frac{1}{ ln9 } \times ln9 \times {9}^{x} = {9}^{x} \\ y'( x_{0} ) = y'(1) = 9$