Question

a)(x-6)^2-x^2=0
б)y(y-1)-(y-5)^2=2

Answer 1

Объяснение:

а) x²-12x+36-x²=0

-12x=-36

x=3

б)y²-y-y²+10y-25=2

9y=27

y=3

Answer 2

Ответ:

$(x - 6) {}^{2} - x {}^{2} = 0\\ = x {}^{2} - 12x + 36 - x {}^{2} = 0 \\ - 12x + 36 = 0 \\ - 12x = - 36 \\ x = - 36 \div - 12 \\ x = 3$